# Molecular Weight and the Mole

The weight of a molecule is the sum of the weights of the atoms of which it is made.

The unit of weight is the dalton, one-twelfth the weight of an atom of 12C. Thus the molecular weight (MW) of water is 18 daltons. (We shall ignore the tiny error introduced by the presence of traces of other isotopes - 17O, 18O, and 2H among the predominant 1H and 16O atoms.)

Why is it important to know the molecular weight of a compound?

For an example, let us assume that you want to study the response of honeybees to solutions of various kinds of sugars. One way to do this would be to make up several different solutions and see which one the bees prefer to harvest.

You might offer the bees the choice between, say, a 35% solution of sucrose (common table sugar) and a 35% solution of glucose (a natural component of honey). This would involve, in each case, dissolving 350 parts by weight (e.g., grams) of sugar in 650 parts (g) of water, thus producing 1000 g of each solution.

But there is a problem with this approach. The willingness of the honeybee to respond to the presence of sugar dissolved in water is dependent on the number of sugar molecules in a given volume of the solution.

The sucrose molecule (MW = 342) is almost twice as heavy as the glucose molecule (MW = 180). So a 35% solution of glucose would contain almost twice as many molecules as a 35% solution of sucrose. To correct the problem, you should make the solution with the weights of sucrose and glucose in a ratio of 342:180. Then you would have the same concentration of molecules in each; that is, drop for drop, each solution would contain the same number of molecules.

If you weight out exactly 342 grams (g) of sucrose, you will have weighed out 1 mole of it. That is,

a mole is the quantity of a substance whose weight in grams is equal to the molecular weight of the substance.

Thus 1 mole of glucose weighs 180 g. Furthermore, if you dissolve 1 mole of a substance in enough water to make 1 liter (L) of solution, you have made a 1-molar (1 M) solution.
 Link to discussion of the units used in scientific work.

A 1 M solution of these sugars would probably be too strong for the experiment with the bees. It might be better to make up a liter of each solution containing 34.2 g and 18.0 g respectively. Such solutions would be designated one-tenth molar (0.1 M) solutions. Drop for drop, these two solutions would still contain exactly the same number of molecules because they are of the same molarity.